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Can anyone do these challenging math problems? or help me?
please explain how… thanks so much. BTW, the numbers (like J.14) of the questions are for my reference.
J.14 – A box of golf tees contains 3 red tees, 5 green tees, 6blue tees, and 4white tees. if 4tees are selected w/o replacement, wat is the probability that all 4 tees are different colors?
J.24- Suppose that we know that 10% of all Americans prefer dogs to cats and that 4 out of 5 people who prefer dogs are men. what proportion of men prefer dogs, and what proportion of women prefer dogs?
J. 22- how would u enlarge a picture by a factor of 2 using repeated enlargements on a copy machine that can enlarge only up to 155% and only in integer increments?
D.29- find all positive integers n so that n^3-2 is a multiple of n-4.
O.18- connect successive trisection points on the sides of a square to form an octagon. The area of the octagon could be used to approx. the area of the circle inscribed in the square. areas of circle%square are =. what value of pi would be implied?
J.14: The factor for the first tee would be, of course, 1. The factor for the second tee would depend on what color you got for the first tee. The total number of tees is 18, so for each color possibility for the first one, you would have to put the total of the remaining tees of different colors over 17 for the factor on the second tee. The factor for the third tee would depend on what colors you got for tees one and two, and so on. This sounds very complex; however, I think you would find that, no matter which way you tried it, you would get the same set of numerators and the same set of denominators, just in different places. So, when you multiply the four factors together, no matter what order you pick the colors in, you would always get the same answer. Just do one example carefully, and that should be it.
J.24: That seems easy: 4/5 x 10% = 8% of men prefer dogs, and 1/5 x 10% of women prefer dogs. If you want the preferences for cats, just subtract those numbers from 100%.
J.22: I would go for the square root of two, which is 1.414… Since the copier can only do whole numbers from 1 to 155, I would use x141% on the first scan, and 142% on the second. Multiply those two together (in decimal form), 1.41 x 1.42 = 2.0022, which is as close as you’re going to get in two scans. I think.
The other two have me stumped, too. Good luck.
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